见图
设：
t=x1/2
x1/2+x-1/2=3
t+1/t=3
则
t^2+1/x^2=7
(x3/2+x-3/2-3)/(x2+x-2-2)
=(t^3+1/t^3-3)/(t^2+1/x^2-2)
=[(t+1/t)(t^2+1/x^2-1)-3]/(t^2+1/x^2-2)
=[3*(7-1)-3]/(7-2)
=15/5
=3
（X3/2+X-3/2-3）=X（X1/2+X-1/2-3）后面你会解了吧（3-3）=几？
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